The five girls, named G1, G2,…G5 arranged the round-table sitting so that between each two of them there were at least two out of 12 boys , B1, B2,…B12.

In how many ways is such arrangement possible?

(In reply to re: solution by Larry)

I missed that "two" rather than one; I'll have to revamp my calculation.

Posted by Charlie on 2023-10-02 21:21:22