Cars on the road (Posted on 2004-04-09)

	Submitted by SilverKnight
Rating: 2.5000 (4 votes)
Solution:	(Hide)
If the probability of seeing a car is 609/625, then the probability of NOT seeing a car is 1 - 609/625 = 16/625. This means that if we must not have seen a car in each of FOUR five minute periods. So we must multiply the likelihood of NOT seeing a car in each five minutes, x (4 times) and get 16/625. x^4 = 16/625 x = 2/5 Since the question asked about the likelihood of SEEING a car in 5 minutes, we must subtract that likelihood from 1... 1 - 2/5 = 3/5, the answer. ___________________________ Problem found at: http://www.techinterview.org/Puzzles/carsontheroad.html

	Subject	Author	Date
	Carfast Express	CodyDunning	2023-12-29 04:50:54
	No Subject	JamesYawn	2023-02-20 10:50:06
	Solution To The Problem	K Sengupta	2007-04-17 11:35:26
	puzzle solution	K Sengupta	2007-04-17 11:29:00
	hmm	ofnoconcern	2004-11-28 15:19:55
	Alternative to Poisson	Charlie	2004-04-10 14:17:42
	re(6): One Mean Poisson = Shark	Penny	2004-04-09 21:53:52
	re(5): One Mean Poisson = Shark	Richard	2004-04-09 21:35:36
	re(4): One Mean Poisson = Shark	Penny	2004-04-09 21:19:04
	re(3): One Mean Poisson = Shark	Richard	2004-04-09 21:13:53
	re(2): One Mean Poisson = Shark	Penny	2004-04-09 19:28:46
	re: One Mean Poisson = Shark	Larry	2004-04-09 19:16:04
	One man's Mean is another man's Poisson	Penny	2004-04-09 16:01:24
	Solution	Rajat	2004-04-09 15:37:15
	re(4): Auto-suggestion	ThoughtProvoker	2004-04-09 15:31:28
	re(3): Auto-suggestion	Charlie	2004-04-09 14:50:43
	re(3): Auto-suggestion	Richard	2004-04-09 14:28:47
	re(2): Auto-suggestion	ThoughtProvoker	2004-04-09 13:43:53
	re: Auto-suggestion	Charlie	2004-04-09 13:38:18
	Solution	Jer	2004-04-09 12:13:22
	Auto-suggestion	Penny	2004-04-09 12:01:02
	answer	Ady TZIDON	2004-04-09 11:17:28