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Yet Another 0=1 (Posted on 2004-07-08) Difficulty: 2 of 5
Find the error in this proof of 0=1:

∫(1/x) dx
= ∫(1/x)*(1) dx (Mult. Identity)
= (1/x) x - ∫(-1/x^2)*x dx (Integ by Parts)
= 1 + ∫(1/x) dx (Simplify)

Hence, ∫(1/x) dx = 1 + ∫(1/x) dx, therefore 0 = 1.

See The Solution Submitted by Brian Smith    
Rating: 1.5000 (6 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionK Sengupta2007-10-14 04:06:39
SolutionNo Subjectvije2004-07-17 13:31:22
re(3): SolutionEric2004-07-13 15:42:03
re(2): SolutionBon2004-07-13 00:45:11
Some Thoughts...Cesar Ali2004-07-10 00:28:10
SolutionBrian's proof is almost right!Larry2004-07-08 21:58:29
re(2): Solutionnp_rt2004-07-08 20:47:41
re: SolutionEric2004-07-08 16:31:09
Solutionnp_rt2004-07-08 16:11:44
SolutionSolutionEric2004-07-08 12:50:24
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