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Yet Another 0=1 (Posted on 2004-07-08) Difficulty: 2 of 5
Find the error in this proof of 0=1:

∫(1/x) dx
= ∫(1/x)*(1) dx (Mult. Identity)
= (1/x) x - ∫(-1/x^2)*x dx (Integ by Parts)
= 1 + ∫(1/x) dx (Simplify)

Hence, ∫(1/x) dx = 1 + ∫(1/x) dx, therefore 0 = 1.

See The Solution Submitted by Brian Smith    
Rating: 1.5000 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Brian's proof is almost right! | Comment 5 of 10 |
The following statement IS true:
0=1 plus a constant
  Posted by Larry on 2004-07-08 21:58:29
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