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Year by Year (Posted on 2004-11-23) Difficulty: 4 of 5
Consider N=2004^2004.

1) What are the first 3 digits of N?

2) What are the last 3 digits of N?

See The Solution Submitted by SilverKnight    
Rating: 2.3333 (6 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionSolution To Part II of N = 1996^1996K Sengupta2007-10-18 06:31:33
SolutionSolution To Part IIK Sengupta2007-10-18 06:28:07
SolutionSolution To Part IK Sengupta2007-10-18 06:27:12
cool...sragen2004-11-30 05:41:36
Or use a really big calculator...Jer2004-11-23 17:33:37
re: alternate method (not tested)Charlie2004-11-23 16:28:43
alternate method (not tested)Larry2004-11-23 15:35:19
Solutionsolution (spoiler)Charlie2004-11-23 15:11:39
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