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Year by Year (Posted on 2004-11-23)

Consider N=2004^2004.

1) What are the first 3 digits of N?

2) What are the last 3 digits of N?

See The Solution Submitted by SilverKnight

Rating: 2.3333 (6 votes)

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Solution To Part II of N = 1996^1996	K Sengupta	2007-10-18 06:31:33
Solution To Part II	K Sengupta	2007-10-18 06:28:07
Solution To Part I	K Sengupta	2007-10-18 06:27:12
cool...	sragen	2004-11-30 05:41:36
Or use a really big calculator...	Jer	2004-11-23 17:33:37
re: alternate method (not tested)	Charlie	2004-11-23 16:28:43
alternate method (not tested)	Larry	2004-11-23 15:35:19
solution (spoiler)	Charlie	2004-11-23 15:11:39

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