Too many threes and sixes (Posted on 2005-05-25)

	Submitted by pcbouhid
Rating: 4.0000 (5 votes)
Solution:	(Hide)
Since 6 = 3 x 2, the product in question will be the same as that obtained by multiplying the integer A1 consisting of 666 digits 9, by the integer B1 composed of 666 digits 2. A1 is 1 less than 10^666 (the digit 1 with 666 zeros). So, when B1 is multiplied by A1, the result is the same as multiplying B1 by 10^666 (wich yields an integer composed of 666 digits 2 followed by 666 zeros), and subtracting the integer B1. So the result is clearly 222...2221777...7778, with 665 2's and 665 7's. So the digits that appear in the given product are 1, 2, 7 and 8.

	Subject	Author	Date
	Solution	Dej Mar	2008-11-06 09:07:43
	Answer	K Sengupta	2008-11-06 05:55:44
	re: A Possible Answer	pcbouhid	2005-05-30 16:48:22
	re: A Possible Answer	Sarah	2005-05-30 03:03:03
	A Possible Answer	Sarah	2005-05-30 03:00:43
	No Subject	Laura	2005-05-25 20:32:43
	re: Solution with proof	Jer	2005-05-25 18:48:56
	Solution with proof	Old Original Oskar!	2005-05-25 18:29:13
	PRODUCTIVE PRODUCT	Ady TZIDON	2005-05-25 18:10:44
	There is a pattern to it	Jer	2005-05-25 18:09:00