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2003 - An odyssey with pi and e (Posted on 2005-10-09) Difficulty: 3 of 5
These are the initials decimals of pi and e:

Decimals of pi: 1415926535897932384626433832795...
Decimals of e : 7182818284590452353602874713526...

Without rearranging the order of the digits, add any quantity of parentheses and arithmetic signs +, -, *, / (with same manner in both line) so that to make correct arithmetic expressions equally to 2003, using the least possible number of symbols. You have to use the digits starting from the left one, and the same numbers of digits in each case.

Example for number 11, using the first 5 digits:

- (1 * 4) + 1 + 5 + 9 = 11
- (7 * 1) + 8 + 2 + 8 = 11

These two expression contains 12 symbols (5 digits, 2 parentheses and 5 arithmetic signs).

  Submitted by pcbouhid    
Rating: 3.1111 (9 votes)
Solution: (Hide)
Using 21 symbols:

1 * (41 * 5 - 9 + 26) + 5 * 358 - 9 = 2003
7 * (18 * 2 - 8 + 18) + 2 * 845 - 9 = 2003

1 * 4 + 1 * 59 * 2 - 6 + 5 * 358 + 97 = 2003
7 * 1 + 8 * 28 * 1 - 8 + 2 * 845 + 90 = 2003

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re(4): easy as pi e - A challengepcbouhid2005-10-15 14:22:54
re(3): easy as pi epcbouhid2005-10-14 22:14:27
re(2): easy as pi ebrad2005-10-14 21:49:13
re: easy as pi epcbouhid2005-10-14 12:06:01
Solutioneasy as pi ebrad2005-10-14 10:10:45
I think this hint is sufficient...itīs indeed too hard.pcbouhid2005-10-13 23:48:37
re: 1 st trial ..............13 digits one pair of ()pcbouhid2005-10-13 23:41:52
Solution1 st trial ..............13 digits one pair of ()Ady TZIDON2005-10-13 22:18:17
Hint for those who are trying...pcbouhid2005-10-13 21:12:44
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