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The Descending Integers (Posted on 2006-02-02) Difficulty: 3 of 5
Let us consider all possible positive whole numbers (not containing any leading zeroes) with the proviso that in each of the numbers, none of its digits can be repeated.

Note: any given number may or may not contain all the digits from 0 to 9 (Examples: 7; 20; 1056; 3067941825 etc.)

These numbers are now arranged in descending order of magnitude.

What would be the 200,136th number?

  Submitted by K Sengupta    
Rating: 2.8000 (5 votes)
Solution: (Hide)
The required number is 9,403,152,678.

EXPLANATION:

At the outset, the total number of integers commencing with 9 and possessing all the nine digits is 9! = 362,880.

Since, 200,136 is less than 362,880; it follows that the first digit must be equivalent to 9.

Since, all the digits are non-repetitive, the value of the second digit is 8 or less.

Now, 200,136 = 4*(8!) + 38,856 and accordingly, the second digit must be 8-4=4.

38,856 = 7*(7!) + 3,576. since the third digit must contain one of 8,7,6,5,3,2,1,0 ; it follows that the said digit must correspond to 0.

3,576 = 4*(6!) + 696. Since, the fourth digit must contain one of 8,7,6,5,3,2,1 it follows that the said digit must correspond to 3.

696 = 5*(5!) + 96. Since, the fifth digit must contain one of 8,7,6,5,2,1 ; it follows that the said digit must correspond to 1.

96 = 3*(4!) + 24. Sice the sixth digit must contain one of 8,7,6,5,2 ; it follows that the said digit must be equal to 5.

Now, 24 = 4!. Accordingly, the digits of the smallest four digit number constituted by 8,7,6,2 must correspond to the last four digits and consequently, the last four digits ( written from left to right) are 2,6,7,8 giving the required number as 9,403,152,678.

---------Q E D-----------

COMPUTER SOLUTION (Submitted By Charlie):

By taking the permutations of all ten digits in ascending order of value, and counting down from 10! = 3628800, when we get to a count of 200136, that will be the 200,136th in descending order.

DECLARE SUB permute (a$)
DEFLNG A-Z
CLS
a$ = "0123456789": h$ = a$
ct = 3628800
DO
permute a$
ct = ct - 1
LOOP UNTIL a$ = h$ OR ct = 200136
PRINT a$

The permute subroutine is shown elsewhere on this site.

The answer agrees, as 9403152678.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
AcknowledgementsK Sengupta2006-03-15 01:13:34
SolutionCorrect Solution by handBill Matthews2006-02-04 07:56:17
I see my error...Dej Mar2006-02-03 01:25:39
My calculationsDej Mar2006-02-03 01:23:22
If my calculations have been correct,,,,Dej Mar2006-02-02 21:32:34
Solutionre: solution -- computer confirmationCharlie2006-02-02 12:45:28
re: solution I agreegoFish2006-02-02 12:38:48
SolutionsolutionCharlie2006-02-02 12:23:32
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