All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Walking down an escalator (Posted on 2006-03-29)
On a working escalator, one man walking down it took 50 steps. Another man, walking three times faster, took 75 steps.

How many steps would each man take going down the same escalator during a power outage?

 No Solution Yet Submitted by Jer Rating: 3.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 solution | Comment 2 of 10 |

Let the number of steps to come down = x.

Let the person who walked 50 steps is A and the other one is B.

No of steps rolled in by the esculator when A is walking down = x - 50. similarly for B is  x - 75

The time take by A to walk 1 step down = The time take by B to walk 3 steps down

By the time A walked 1 step, the no. of steps rolled in by the esculator = (x - 50)/50

By the time B walked 3 step, the no. of steps rolled in by the esculator = 3(x - 75)/75

therefore    (x - 50)/50  =  3(x - 75)/75

x = 100

So the steps each man took to go down the escalator during a power outage is 100

 Posted by Jp on 2006-03-30 01:33:37

 Search: Search body:
Forums (0)