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Twist in Sequence (Posted on 2006-11-16) Difficulty: 2 of 5

            | 59
+---+---+---+---
|   |   |   | 94
+---+---+---+---
|   |   |   | 81
+---+---+---+---
|   |   |   |110
+---+---+---+---
|194| 41| 50|107
The numbers are the totals of the rows, columns and diagonals
of a 'magic square'.

Describe the common sequence which they hide.

See The Solution Submitted by brianjn    
Rating: 4.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution | Comment 5 of 9 |
(In reply to re: uniqueness of the numbers by Jyqm)

Using any integer solution as a "base", one easy way to generate more integer solutions is the following:

A B C

D E F

G H J

Subtract 2 from B

Add 2 to H

Add 1 to both A and C

Subtract 1 from both G and J

So for example, using your solution and following the above steps once through you get the following integer solution which also works:

81   9     4

59   1   21

54  31  25 

Once I saw that, it became obvious what the "common sequence" must be, and a little more tweaking gives the intended solution:

81   4    9

64   1   16

49  36  25

Edited on November 16, 2006, 5:41 pm
  Posted by tomarken on 2006-11-16 15:51:54

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