All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 A Reciprocal And Square Problem (Posted on 2007-07-10)
Find all real pairs (p, q) satisfying the following system of equations:
p - 1/p - q2 = 0

q/p + pq = 4

 See The Solution Submitted by K Sengupta Rating: 3.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 computer aided solution | Comment 3 of 7 |

The curve of q^2 = p – 1/p, with q as the dependent variable consists of a parabola-like figure with it's axis being the p axis (independent variable axis) and vertex at (1,0) in union with a curve going through (-1,0) asymptotically approaching the q axis towards +infinity and also asymptotically approaching the q axis towards -infinity.

The curve q = 4/(1/p + p) is valid for all real p (if we define (0,0) as part of the curve, but this doesn't play into the solution). It has negative q for negative p and positive q for positive p and is in fact what's called an odd function; q approaches zero as p becomes larger or as p becomes smaller; q is a minimum at (-1,-2) and maximum at (1,2).  It intersects the other graph in each of the two parts described above. One of the intersections has 2<p<3, 1<q<2, and the other has –1<p<0, -2<q<-1. From a graph we can see there are no other solutions, as the first equation has no values of p < -1 and values of q get farther from zero for higher values of p than 1, while values of q approach zero for larger values of p in the other equation.

The following program finds the positive solution:

DEFDBL A-Z

p = 2.5: q = 1.4

CLS

DO

prevP = p: prevQ = q

p = ((4 + SQR(16 - 4 * q * q)) / (2 * q) + p) / 2

q = (SQR(p - 1 / p) + q) / 2

PRINT p; q, p * p; q * q

LOOP UNTIL prevP = p AND prevQ = q

Which displays as its final iteration:

`2.414213562373095  1.414213562373095      5.82842712474619  2`

for p, q, p^2 and q^2.  So this solution is q=sqrt(2), p=sqrt(2) + 1, which checks out by plugging in to the equations.

By inspection, guided by the above solution and the graph, the other solution is q=-sqrt(2), p=1-sqrt(2).

Edited on July 10, 2007, 11:16 am
 Posted by Charlie on 2007-07-10 11:16:04

 Search: Search body:
Forums (0)