All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Curious Real Additive Relationship II (Posted on 2008-05-28) Difficulty: 2 of 5
Refer to the earlier problem.

Can you find all possible non zero real quadruplet(s) (P, Q, R, S) that satisfy the following system of simultaneous equations?

2*Q = P + 19/P, and:

2*R = Q + 19/Q, and:

2*S = R + 19/R, and:

2*P = S + 19/S.

Bonus Question:

In the problem given above, if the number 19 was replaced throughout by a real constant M > 1, what would have been the possible non zero real quadruplet(s) (P, Q, R, S) that satisfy the given set of equations, in terms of M?

See The Solution Submitted by K Sengupta    
Rating: 2.5000 (2 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: SolutionK Sengupta2008-07-28 11:57:58
SolutionSolutionPraneeth2008-05-30 07:12:49
Some ThoughtsMore generally ...Steve Herman2008-05-28 17:01:29
SolutionAha! (spoiler)Steve Herman2008-05-28 16:56:56
An obvious start (spoiler)Steve Herman2008-05-28 13:56:14
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information