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Almost equal (Posted on 2011-04-01) Difficulty: 1 of 5
Integers equal to each other or differing by 1 will be called "almost equal " within the contents of this problem.

In how many ways can 2011 be expressed as a sum of almost equal addends?
The order of the addends in the expression is immaterial.

See The Solution Submitted by Ady TZIDON    
Rating: 3.7500 (4 votes)

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Hints/Tips re: April Fool's answer R E A D T H I S | Comment 2 of 10 |
(In reply to April Fool's answer by Steve Herman)

Your answer fits the date PERFECTLY.

On a more POSITIVE note, allow me to rephrase the question:

In how many ways can 2011 be expressed as a sum of almost equal  POSITIVE addends?

New answer  is welcome!


  Posted by Ady TZIDON on 2011-04-01 13:39:56
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