Given an equation ax^2+bx+c=0
what values a,b cause the roots of the equation to be a and b and the discriminant to be equal to c?
In case anyone was wondering, it doesn't work out nicely into real numbers. Note if a=0 or b=0, then c=a^2 b implies c=0. But then c=b^24ac gives b=0, which means a=0 since the roots of ax^2=0 are zero.
Solving the equation c=b^24ac for c gives (4a+1)c=b^2; plugging in c=a^2 b gives (4a+1)(a^2 b)=b^2, so (4a+1)(a^2)=b. Plugging in b in terms of a gives (4a+1)(a^2)=a^2/(a+1) and so (4a+1)(a+1)=1 and finally 4a^2+5a+1=1
At this point, one can notice this equation has no real roots, and thus a and b will be complex. I did some extra computations to check the work, giving
a= 0.625 + 0.330718914 i
b=0.125 + 0.992156742 i
c=0.4453125 + 0.227369253 i
For the other set of values, simply change the plus to minus.

Posted by Gamer
on 20110630 00:09:09 