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P/Q (Posted on 2012-10-12) Difficulty: 4 of 5
Evaluate P/Q, given:

P= 1-2-2+4-2-5-2+7 -2-8-2+10-2 -11-2+13-2-14-2+...

Q= 1+2-2-4-2-5-2+7 -2+8-2-10-2 -11-2+13-2+14-2+...

No Solution Yet Submitted by Ady TZIDON    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Possible answer | Comment 1 of 5
((1/(6n+1)^2-1/(6n+2)^2+1/(6n+4)^2-1/(6n+5)^2)/((1/(6n+1)^2+1/(6n+2)^2-1/(6n+4)^2-1/(6n+5)^2))) is worth 1/3 in the limit, according to wolframalpha.

On reflection, possibly a bit unfair to wolframalpha. The exact expression is:

(sum n=0 to infinity ((1/(6n+1)^2-1/(6n+2)^2+1/(6n+4)^2-1/(6n+5)^2))/(sum n=0 to infinity (1/(6n+1)^2+1/(6n+2)^2-1/(6n+4)^2-1/(6n+5)^2))), [for the precise wolframalpha syntax required see comment 4]

so the original version was open to misinterpretation.



Edited on October 13, 2012, 10:24 am
  Posted by broll on 2012-10-12 10:31:35

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