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Deux Digit Determination (Posted on 2014-11-13) Difficulty: 3 of 5
Find the last two digits in the base ten expansion of :

C(2014, 1) + 22*C(2014, 2) + 32*C(2014, 3) + ......+ 20142*C(2014, 2014)

**** C is the choose function, that is:
C(m,n) = m!/(n!*(m-n)!)

See The Solution Submitted by K Sengupta    
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Comments: ( Back to comment list | You must be logged in to post comments.)
re: Full expansion, but unproven result | Comment 3 of 4 |
(In reply to Full expansion, but unproven result by Jer)

Calculating 4058210*2^2012 in UBASIC (under DOSBox) does come out equal to the number calculated directly in my computer solution.
  Posted by Charlie on 2014-11-13 14:29:50

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