All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Equation Exercise (Posted on 2014-12-16) Difficulty: 2 of 5
a,b,c,d and e satisfy this system of equations:

2a+b+c+d+e = 6
a+2b+c+d+e = 12
a+b+2c+d+e = 24
a+b+c+2d+e = 48
a+b+c+d+2e = 96

Find 3d+2e without solving the above system.

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionAnother solutionBrian Smith2016-11-24 16:02:23
Solutionsolving as little as possibleJer2014-12-16 13:48:49
SolutionsolutionDej Mar2014-12-16 11:05:52
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (2)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2021 by Animus Pactum Consulting. All rights reserved. Privacy Information