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An ancient Egyptian problem (Posted on 2015-02-13) Difficulty: 3 of 5
Solve in integers:
4/n=1/x+1/y+1/z, n>1

No Solution Yet Submitted by Ady TZIDON    
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Some simple solutions | Comment 1 of 5
1/2+1/3+1/6=1=4/4

1/(2a)+1/(3a)+1/(6a)=4/(4a)
[all solutions can be generalized this way]

1/3 + 1/9 + 1/18 = 1/2 = 4/8

Since you allow negatives
If a>0
1/a + 1/b +1/(-b) = 1/a = 4/(4a)





  Posted by Jer on 2015-02-13 13:36:37
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