Three cubes of volume 1, 8, and 64 are glued together.
What is the smallest possible surface area of the resulting configuration?
-Problem taken from UNL Math Day
64!
just glue one inside of each other
put the 1 insidee the 8 and those inside of the 64
:-)
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Posted by Joe C
on 2004-02-25 09:30:53 |