Consider N=2004^2004.
1) What are the first 3 digits of N?
2) What are the last 3 digits of N?
What a cool calc it's is... but i still curious if there is another way to find first 3 digit of 2004^2004.. good job for you Jer... it's very shock me with your number's... maybe it can be a sequences... :p
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Posted by sragen
on 2004-11-30 05:41:36 |