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A few coins (Posted on 2004-11-19) |
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In Levikland, there are coins worth 1, 2, 5, 10, 20, 50 and 100 perplexii. A has twice as much money as B, who has twice as much as C, who has twice as much as D. How can this be, if everybody has two coins?
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Submitted by e.g.
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Rating: 2.9231 (13 votes)
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Solution:
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(Hide)
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A has 8 times as much as D, so we must find a way to make a number with 2 coins so 1/8 of that number can also be made. A=120 (100+20) and D=15 (10+5) is the solution, with B=60 (50+10) and C=30 (20+10). |
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