Sums and Products (Posted on 2003-03-12)

	Submitted by Ravi Raja
Rating: 2.8000 (10 votes)
Solution:	(Hide)
Let the numbers be chosen as (n-1), n and (n+1). Then the sum of their resulting quotients when their product is divided by each of them is: n(n+1) + (n+1)(n-1) + n(n-1) which is equal to 74. Therefore, we have: n(n+1) + (n+1)(n-1) + n(n-1) = 74 Which on simplification gives: (n)^2 = 25 which implies n = (-5) or n = (+5) Thus, the three consecutive numbers are: (-6,-5,-4) or (4,5,6).

	Subject	Author	Date
	re(2): Another Solution + misinterpretation	Goss2	2023-06-13 01:33:44
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