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Some Factorials Sum Power (Posted on 2008-12-21) |
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Determine all possible pair(s) (P, Q) of positive integers that satisfy this equation.
P! + Q! = PQ
where P and Q are not necessarily distinct.
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Submitted by K Sengupta
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Rating: 5.0000 (1 votes)
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Solution:
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(Hide)
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(P, Q) = (2,2) and (2,3) are the only solutions to the given problem.
For an explanation and proof, refer to the solution submitted by Daniel in this location.
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