perplexus.info :: Numbers : Flying Low

Flying Low (Posted on 2010-08-05)

Substitute each of the letters by a different digit from 0 to 9 to satisfy this system of alphametic equations. None of the numbers as well as none of the exponents contains a leading zero.

(DID)^W = F^XA, and:
(FLY)^A = Y^LI, and:
(LOW)^O = I^LT

Submitted by K Sengupta

Rating: 3.5000 (2 votes)

Solution: (Hide)

The letter to digit substitution is as follows:
T X L D I O A Y 0 1 2 3 4 5 8 9 343 ^ 6 = 7 ^ 18 729 ^ 8 = 9 ^ 24 256 ^ 5 = 4 ^ 20
For an explanation, refer to the solution submitted by Daniel in this location and by Charlie in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
re: my way	ed bottemiller	2010-08-05 14:17:04
UBASIC solution	Charlie	2010-08-05 12:59:53
my way	Ady TZIDON	2010-08-05 12:18:30
mathematica solution	Daniel	2010-08-05 11:52:53
Clarification?	ed bottemiller	2010-08-05 11:42:38

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