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Unknown Power Ponder (Posted on 2014-08-11) Difficulty: 3 of 5
Each of x, y and z are positive integers such that x+y+z=2006 and, x!*y!*z! = p*10q, where each of p and q is a positive integer and p is not divisible by 10.

What is the smallest value of q?

  Submitted by K Sengupta    
Rating: 5.0000 (1 votes)
Solution: (Hide)
The required smallest value of q is 492.

For an explanation, refer to the solution submitted by Steve Herman in this location and the rejoinder by broll in this location.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Hints/Tipsre(3): Paper and pencil solution (spoiler?)Ady TZIDON2014-08-12 09:49:12
Some Thoughtsre(2): Paper and pencil solution (spoiler?)broll2014-08-12 08:17:35
Solutionre: Paper and pencil solution (spoiler?)Ady TZIDON2014-08-12 02:21:07
SolutionPaper and pencil solution (spoiler?)Steve Herman2014-08-11 21:01:22
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