perplexus.info :: Just Math : Omega to Alpha Observation

Omega to Alpha Observation (Posted on 2014-12-23)

Find the smallest value of hexadecimal positive integer N which becomes 4*N when the last digit of N is moved to be the first. For example, turning (2345)₁₆ into (5234)₁₆. How about 2*N? 7*N? 8*N?

Submitted by K Sengupta

Rating: 4.0000 (2 votes)

Solution: (Hide)

(I) 4*(104)₁₆ = (410)₁₆
(II) 2*(10842)₁₆ = (21084)₁₆
(III) 7*(1024E6A17)₁₆ = (71024E6A17
(IV) 8*(1020408)₁₆ = (8102040)₁₆
For explanations to (I) and (II), refer to the solution submitted by Charlie in this location.
For (III) and (IV), refer to the solutions submitted by Dej Mar here and here.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
re(2): 7*n, analytically	Steve Herman	2014-12-24 10:02:05
re: 7*n, analytically	Dej Mar	2014-12-24 08:06:23
7*n, analytically	Steve Herman	2014-12-23 19:07:44
re: computer solutions	Dej Mar	2014-12-23 16:30:39
computer solutions	Charlie	2014-12-23 15:09:46

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