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Politically Correct Moduli (Posted on 2005-09-03) Difficulty: 4 of 5
The quadratic equation x^2-3x+2=0 has the "correct" number of solutions modulo 5 and 7. However, modulo 6 the equation has four solutions; namely, 1, 2, 4, and 5. For what positive integers n does the equation x^2-3x+2=0 have exactly two incongruent solutions modulo n?

  Submitted by McWorter    
Rating: 4.0000 (2 votes)
Solution: (Hide)
Answer: powers of a single prime. If x^2-3x+2 is congruent 0 modulo n=p^k, where p is a prime, then, since x-1 and x-2 are relatively prime, p divides only one of x-1 and x-2. Hence x is congruent 1 or 2 modulo n.

On the other hand, let n=ab, where a and b are relatively prime and both greater than 1. Then there exist integers u and v such that au+bv=1. Set x=au+1. Then x=-bv+2 as well. Hence x-1 is divisible by a and x-2 is divisible by b. Thus the product, x^2-3x+2, is congruent 0 modulo n=ab. The integer x=-bv+2 is not congruent to 1 modulo n because this implies bv is congruent 1 modulo n, contradiction. Similarly, x is not congruent 2 modulo n. Hence x^2-3x+2 has at least three incongruent roots modulo n=ab.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Puzzle Thoughts K Sengupta2023-07-28 01:26:34
re(7): ProofMcWorter2005-09-04 05:39:40
re(6): ProofRichard2005-09-04 04:38:50
re(5): ProofMcWorter2005-09-04 03:51:18
re(4): ProofRichard2005-09-04 01:04:08
re(3): ProofMcWorter2005-09-03 23:38:59
re(2): ProofRichard2005-09-03 23:09:09
re: ProofMcWorter2005-09-03 21:20:24
SolutionProofTristan2005-09-03 20:55:03
Solutionbases that work; and those that don'tCharlie2005-09-03 18:22:16
re: I think the answer is...Richard2005-09-03 17:52:56
Some ThoughtsI think the answer is...Tan Kiat Chuan2005-09-03 16:39:15
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