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Going Greatest With 2007 (Posted on 2007-11-04) |
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Determine the total number of real y with 1 ≤ y ≤ 2007 satisfying this equation:
[y/2] + [y/3] + [y/8] + [y/9] = 77y/72
where [p] denotes the greatest integer ≤ p.
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