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Quadrilateral in a rectangle (Posted on 2009-07-17) Difficulty: 2 of 5
Given a rectangle with diagonal length d. On each side pick an arbitrary point that is not a corner.
Let u, x, y, and z be the side lengths of the convex quadrilateral determined by these four points.

Prove that
   d2 ≤ u2 + x2 + y2 + z2 < 2d2.

See The Solution Submitted by Bractals    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(3): Solution - your reason to edit | Comment 4 of 5 |
(In reply to re(2): Solution - your reason to edit by Harry)

Yes, I've found that the special characters from the special-character button on the comment editor give bad results, as in for a capital sigma.  It looks good here in the comment box, but I'm confident that once this is posted, that won't look like a capital sigma.
  Posted by Charlie on 2009-07-19 13:07:02

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