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Equal Tangents (Posted on 2010-10-03) Difficulty: 3 of 5
C(UV) denotes the circle with diameter UV.

T(P,QR) denotes the tangential distance |PS|,
where point P lies outside C(QR), point S
lies on C(QR), and PS is tangent to C(QR).

Let A, B, C, and D be distinct, collinear
points in that order.

Construct a point E on line AD such that
|EF| = T(E,AB) = T(E,CD) = |EG|





















See The Solution Submitted by Bractals    
Rating: 3.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re(3): ConstructionCharlie2010-10-05 01:05:46
Solutionre: Algebraic solution leads to geometricLarry2010-10-04 22:34:19
re(2): Constructionbrianjn2010-10-04 21:13:39
re(2): Does this work?broll2010-10-04 12:20:04
re: Does this work?Charlie2010-10-04 12:16:49
re: ConstructionCharlie2010-10-04 12:05:22
QuestionDoes this work?broll2010-10-04 02:53:11
SolutionConstructionbrianjn2010-10-04 02:20:35
SolutionNo SubjectAdy TZIDON2010-10-03 15:40:05
re: Algebraic solutionBractals2010-10-03 14:39:12
Some ThoughtsAlgebraic solutionLarry2010-10-03 14:14:53
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