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Factorial-Square Sum (Posted on 2014-03-23) Difficulty: 3 of 5
Determine all possible triplets (X,Y,Z) of positive integers that satisfy:

                          X!*Y! = X! + Y! + Z2

Prove that there are no others.

No Solution Yet Submitted by K Sengupta    
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Comments: ( You must be logged in to post comments.)
  Subject Author Date
Some ThoughtsSome analytical conclusionsSteve Herman2014-03-23 16:15:55
re(2): moreAdy TZIDON2014-03-23 13:18:27
re: moreCharlie2014-03-23 10:27:33
Some Thoughtscomputer explorationCharlie2014-03-23 10:19:54
Hints/TipsmoreAdy TZIDON2014-03-23 09:50:56
Hints/TipsmoreAdy TZIDON2014-03-23 09:50:51
Hints/Tipsjust by looking at itAdy TZIDON2014-03-23 09:34:14
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