perplexus.info :: Just Math : Power inequality

Power inequality (Posted on 2005-03-15)

Prove that for all positive x, y, and z,

(x+y)^z+(y+z)^x+(z+x)^y > 2.

Submitted by e.g.

Rating: 3.0000 (1 votes)

Solution: (Hide)

See a proof here.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Second Half of Solution	Andre	2010-05-25 14:09:47
Solution	David	2005-03-28 07:20:39
re(4): Can get close to 2 - what is missing ?	Richard	2005-03-28 03:45:01
re(3): Can get close to 2 - what is missing ?	pcbouhid	2005-03-27 21:45:48
re(2): Can get close to 2 - what is missing ?	Richard	2005-03-27 20:45:15
re: Can get close to 2 - what is missing ?	pcbouhid	2005-03-27 17:21:54
re(4): Can get close to 2	Richard	2005-03-17 19:05:55
re(3): Can get close to 2	pcbouhid	2005-03-17 12:29:35
Conjecture	Richard	2005-03-17 01:00:11
re(2): Can get close to 2	Michael Cottle	2005-03-16 21:30:11
re: Can get close to 2	pcbouhid	2005-03-16 21:03:09
Can get close to 2	Richard	2005-03-16 20:47:26
re(4): am I wrong ?	pcbouhid	2005-03-16 18:43:57
re(3): am I wrong ?	Michael Cottle	2005-03-16 17:57:18
re(2): am I wrong ?	pcbouhid	2005-03-16 13:07:28
Half a solution	Federico Kereki	2005-03-16 01:35:33
re: am I wrong ?	Richard	2005-03-16 00:16:08
am I wrong ?	pcbouhid	2005-03-15 22:23:16

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