perplexus.info :: Just Math : Cubeless?

Cubeless? (Posted on 2004-08-29)

Prove that for any positive integer n, there exists at least one multiple of 5^n that doesn't have any perfect cube digits (0, 1, or 8) in its decimal representation.

See The Solution Submitted by Federico Kereki

Rating: 3.4000 (5 votes)

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Subject	Author	Date
Puzzle Solution	K Sengupta	2007-06-12 11:13:15
Getting There	Bruce Brantley	2004-10-16 10:11:34
Understandable	Bruce Brantley	2004-09-20 10:45:26
re(2): Similar solution	Charlie	2004-08-30 10:54:23
re: Similar solution	Charlie	2004-08-30 10:42:26
Similar solution	e.g.	2004-08-30 08:35:32
Just a thought	Bruce Brantley	2004-08-29 14:37:38

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