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Cubeless? (Posted on 2004-08-29) Difficulty: 3 of 5
Prove that for any positive integer n, there exists at least one multiple of 5^n that doesn't have any perfect cube digits (0, 1, or 8) in its decimal representation.

See The Solution Submitted by Federico Kereki    
Rating: 3.4000 (5 votes)

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  Subject Author Date
SolutionPuzzle SolutionK Sengupta2007-06-12 11:13:15
Getting ThereBruce Brantley2004-10-16 10:11:34
UnderstandableBruce Brantley2004-09-20 10:45:26
re(2): Similar solutionCharlie2004-08-30 10:54:23
re: Similar solutionCharlie2004-08-30 10:42:26
SolutionSimilar solutione.g.2004-08-30 08:35:32
Just a thoughtBruce Brantley2004-08-29 14:37:38
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