perplexus.info :: Just Math : e pluribus unum

e pluribus unum (Posted on 2003-12-08)

Below are three groups of three numbers each. Combine the numbers in each group using the standard binary operations (addition, subtraction, multiplication, division, and exponentiation) so that each group yields the same number (there is one unique solution).

1, 6, 11
13, 20, 33
20, 33, 40

For example, given:
15, 19, 24          11, 30, 36          20, 22, 36
you could make:
24÷(19-15)=6       (30+36)÷11=6         20+22-36=6

See The Solution Submitted by DJ

Rating: 3.8462 (13 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

Don't start that again

| Comment 7 of 11 |

Don't start arguing again

Posted by Minion123 on 2003-12-09 01:29:00

Please log in:

Login:
Password:
Remember me:

Sign up! \| Forgot password

Search:

Search body:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info